> For the complete documentation index, see [llms.txt](https://xtecna.gitbook.io/solucoes-da-beecrowd/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://xtecna.gitbook.io/solucoes-da-beecrowd/ad-hoc/2424-tira-teima.md).

# 2424 - Tira-teima

## Descrição

{% embed url="<https://www.urionlinejudge.com.br/judge/pt/problems/view/2424>" %}

## Solução

Considera um ponto (Px, Py) e um retângulo caracterizado pelos dois pontos opostos (R1x, R1y) e (R2x, R2y) onde o ponto R1 representa o ponto no canto inferior esquerdo e o ponto R2 representa o ponto no canto superior direito. Para sabermos se o ponto P está dentro do retângulo delimitado por R1 e R2, devemos testar se

$$
R1\_{x} \leq P\_{x} \leq R2\_{x} \text{ e } R1\_{y} \leq P\_{y} \leq R2\_{y}
$$

{% tabs %}
{% tab title="C99" %}

```c
#include <stdio.h>

int main()
{
    int X, Y;

    scanf("%d %d", &X, &Y);

    printf("%s\n", (0 <= X && X <= 432 && 0 <= Y && Y <= 468) ? "dentro" : "fora");

    return 0;
}
```

{% endtab %}

{% tab title="C++17" %}

```cpp
#include <iostream>

using namespace std;

int main()
{
    int X, Y;

    cin >> X >> Y;

    cout << (string)((0 <= X && X <= 432 && 0 <= Y && Y <= 468) ? "dentro" : "fora") << endl;

    return 0;
}
```

{% endtab %}

{% tab title="JavaScript 12.18" %}

```javascript
var input = require('fs').readFileSync('/dev/stdin', 'utf8');
var lines = input.split('\n');

let [X, Y] = lines.shift().split(' ').map((x) => parseInt(x));

console.log((0 <= X && X <= 432 && 0 <= Y && Y <= 468) ? "dentro" : "fora");
```

{% endtab %}

{% tab title="Python 3.9" %}

```python
X, Y = [int(x) for x in input().split(' ')]

print("dentro" if 0 <= X <= 432 and 0 <= Y <= 468 else "fora")
```

{% endtab %}
{% endtabs %}


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