Um problema simples de média ponderada.
Uma coisa engraçada desse exercício que os pesos não somam 10 e, por isso, as médias de notas de 0 a 10 na verdade vão de 0 a 11.
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#include <stdio.h>
int main(){
double A, B, media;
scanf("%lf\n%lf", &A, &B);
media = (3.5 * A + 7.5 * B)/11.0;
printf("MEDIA = %.5lf\n", media);
return 0;
}#include <iostream>
#include <iomanip>
using namespace std;
int main(){
double A, B, media;
cin >> A >> B;
media = (3.5 * A + 7.5 * B)/11.0;
cout << "MEDIA = " << setprecision(5) << fixed << media << endl;
return 0;
}let input = require("fs").readFileSync("/dev/stdin", "utf8");
let lines = input.split("\n");
let A = parseFloat(lines.shift());
let B = parseFloat(lines.shift());
let media = (3.5 * A + 7.5 * B) / 11;
console.log(`MEDIA = ${media.toFixed(5)}`);A = float(input())
B = float(input())
media = (3.5 * A + 7.5 * B)/11
print(f"MEDIA = {media:.5f}")